关于CST仿真贴片谐振器的port及边界问题

贴片谐振器如下
  

  
问题一：
在用本征模仿真器仿真模式时，若不设置端口，则正对贴片上方的电壁紧贴着谐振器，是否应该在本征模仿真的时候保留端口?
问题二：
当保留端口使得谐振器在一定边界下谐振，当改变微带基片的边长使之增大时，即减少电边界对仿真结果的影响，本证模仿真出的结果不同
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Mode    Frequency             |                     Accuracy                    
                              |     |(Ax-x)/x|       max(e)         div(e)      
--------------------------------------------------------------------------------
  1     0                     |      1.11e-010        ----         1.63e-008
  2     2.57963616771         |      7.60e-013      1.93e-004      6.50e-008
  3     3.74372737945         |      2.94e-013      2.95e-005      3.35e-008
  4     3.76054820847         |      1.00e-013      2.65e-005      3.45e-008
  5     4.16432758588         |      4.09e-014      6.50e-005      6.20e-008
  6     4.16816813379         |      1.04e-013      7.16e-005      6.29e-008
  7     5.15464943237         |      2.19e-014      3.41e-005      6.42e-008
  8     5.71678646184         |      2.78e-014      3.00e-005      6.17e-008
  9     5.7336521366          |      1.32e-014      2.58e-005      6.93e-008
10     6.32931199582         |      1.82e-014      9.37e-006      3.90e-008
11     6.38262003232         |      8.47e-014      6.98e-006      2.92e-008
12     6.56873986133         |      2.58e-011      2.11e-005      6.88e-008
13     6.57216508396         |      8.84e-012      2.04e-005      6.82e-008
14     7.42921119114         |      6.99e-007      2.49e-005      6.74e-008
15     7.43871872282         |      1.27e-006      2.11e-005      5.82e-008
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Solver Results:
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Mode    Frequency             |                     Accuracy                    
                              |     |(Ax-x)/x|       max(e)         div(e)      
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  1     0                     |      2.39e-012        ----         1.24e-008
  2     2.06720373465         |      4.99e-014      1.49e-004      6.48e-008
  3     3.25513467312         |      2.02e-014      5.16e-005      6.35e-008
  4     3.25649756398         |      2.87e-014      5.78e-005      6.41e-008
  5     3.77447793309         |      1.79e-014      1.87e-005      2.79e-008
  6     3.80113432018         |      2.43e-014      1.50e-005      2.80e-008
  7     4.13680299614         |      1.17e-014      2.83e-005      6.87e-008
  8     4.59815828001         |      2.09e-014      2.39e-005      6.74e-008
  9     4.61073345451         |      4.94e-014      2.34e-005      6.26e-008
10     5.26544661652         |      6.96e-013      1.96e-005      6.91e-008
11     5.26853756161         |      5.64e-014      1.81e-005      6.66e-008
12     5.98949767898         |      1.58e-010      1.78e-005      6.40e-008
13     5.99916205841         |      2.48e-010      1.70e-005      6.66e-008
14     6.16623103692         |      1.34e-005      3.39e-004      2.96e-006
15     6.17071191604         |      4.48e-006      5.60e-005      9.04e-007
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上面第一组数据是边长为80mm，第二组的边长是100mm,
我想问的是，贴片的尺寸和基片面积在多少比例下，仿真结果是可信的?

return loss中振荡点频率是怎么算的啊?

仿真可信度和模型尺寸有什么联系吗?仿真是否准确取决于仿真参数的设置是否正确（在模型尺寸正确的前提下）。