DateAdd Function

Syntax:
DateAdd(inteval, number, dateexpr)
Group: Time/Date
Description:
Return a date value a number of intervals from another date.
Parameter Description

interval This string value indicates which kind of interval to add.
number Add this many intervals. Use a negative value to get an earlier date.
dateexpr Calculate the new date relative to this date value. If this value is Null then Null is returned.
Interval Description

yyyy Year m Month
d Day
w Weekday
ww Week
h Hour
n Minute
s Second
See Also: DateDiff, DatePart.
Example:

Sub Main
Debug
.Print DateAdd("yyyy",1,#1/1/2000#) '1/1/2001
End
Sub