DateAdd Function
Syntax:
DateAdd(inteval, number,
dateexpr)
Group:
Time/Date
Description:
Return a date value a number of intervals from
another date.
Parameter
Description
interval
This string value indicates which kind of interval to add.
number
Add this many intervals. Use a negative value to get an earlier date.
dateexpr
Calculate the new date relative to this date value. If this value is Null then Null is returned.
Interval
Description
yyyy Year
m Month
d Day
w Weekday
ww Week
h Hour
n Minute
s Second
See
Also: DateDiff, DatePart.
Example:
Sub Main
Debug.Print DateAdd("yyyy",1,#1/1/2000#)
'1/1/2001
End Sub